log^2(4x+2)-log^2(x-1)=4

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Solution for log^2(4x+2)-log^2(x-1)=4 equation:


Simplifying
log2(4x + 2) + -1log2(x + -1) = 4

Reorder the terms:
g2lo(2 + 4x) + -1log2(x + -1) = 4
(2 * g2lo + 4x * g2lo) + -1log2(x + -1) = 4
(2g2lo + 4g2lox) + -1log2(x + -1) = 4

Reorder the terms:
2g2lo + 4g2lox + -1g2lo(-1 + x) = 4
2g2lo + 4g2lox + (-1 * -1g2lo + x * -1g2lo) = 4
2g2lo + 4g2lox + (1g2lo + -1g2lox) = 4

Reorder the terms:
2g2lo + 1g2lo + 4g2lox + -1g2lox = 4

Combine like terms: 2g2lo + 1g2lo = 3g2lo
3g2lo + 4g2lox + -1g2lox = 4

Combine like terms: 4g2lox + -1g2lox = 3g2lox
3g2lo + 3g2lox = 4

Solving
3g2lo + 3g2lox = 4

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-4 + 3g2lo + 3g2lox = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 3g2lo + 3g2lox = 0

The solution to this equation could not be determined.

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